If 4m - 2(3 + 2m) + m(2m + 4) = 0, find the values of m.
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4m - 2(3 + 2m) + m(2m + 4) = 0
Expand the brackets and factorize.
4m - (2 x 3 + 2 x 2m) + m x 2m + 4 x m = 0
4m - (6 + 4m) + 2m2 + 4m = 0
4m - 6 - 4m + 2m2 + 4m = 0
4m - 4m + 4m -6 + 2m2 = 0
4m -6 + 2m2 = 0
2m2 + 4m - 6 = 0
Divide both sides by 2
m2 + 2m - 3 = 0
Factorize the expression.
Two numbers when multiplied the resut is -3 and when added the result is 2. The two numbers are 3 and -1.
Express the 2m as 3m - m in order to be able to factorize.
m2 + 2m - 3 = 0
m2 + 3m - m - 3 = 0
m(m + 3)-1(m + 3) = 0
(m + 3)(m - 1) = 0
(m + 3) = 0 or (m - 1) = 0
m + 3 = 0
m = 0 - 3
m = -3
m - 1 = 0
m = 0 + 1
m = 1
m = -3 or 1