Bearing of Q from P = 90^o + 90^o + 65^o

Bearing of Q from P = 245^o

Since two sides are equal, the right angle is isosceles and the base angles are the same.

Base angle = $\frac{\mathrm{180\; -\; 90}}{2}$ = 45°

Bearing starts from the north clockwise. If the angle is less than 100°, begin with a 0.

Bearing starts from the North clockwise.

312° = 270° + 42°

Notes:

1. Bearing starts from the north

2. 300° = 90° + 90° + 90° + 30°

Two of the sides are equal hence it forms an isosceles triangle.

The base angles are equal.

∠ ACB = ∠ CAB = θ

∠ ABC = 60° + 90° = 150°

∠ ACB + ∠ CAB + ∠ ABC = 180° (Sum of interior angles of a triangle)

θ + θ + 150° = 180°

2θ = 180° - 150°

2θ = 30°

Divide both sides by 2

θ = $\frac{\mathrm{30°}}{2}$ = 15°

Bearing of his initial position from his final position = 180° - (θ + 60°)

θ = 15°

Bearing of his initial position from his final position = 180° - (15° + 60°)

Bearing of his initial position from his final position = 180° - 75°

Bearing of his initial position from his final position = 105°

Bearing of Q from P = 90^o + 90^o + 65^o

Bearing of Q from P = 245^o

Since two sides are equal, the right angle is isosceles and the base angles are the same.

Base angle = $\frac{\mathrm{180\; -\; 90}}{2}$ = 45°

Bearing starts from the north clockwise. If the angle is less than 100°, begin with a 0.

Bearing starts from the North clockwise.

312° = 270° + 42°

Notes:

1. Bearing starts from the north

2. 300° = 90° + 90° + 90° + 30°

Two of the sides are equal hence it forms an isosceles triangle.

The base angles are equal.

∠ ACB = ∠ CAB = θ

∠ ABC = 60° + 90° = 150°

∠ ACB + ∠ CAB + ∠ ABC = 180° (Sum of interior angles of a triangle)

θ + θ + 150° = 180°

2θ = 180° - 150°

2θ = 30°

Divide both sides by 2

θ = $\frac{\mathrm{30°}}{2}$ = 15°

Bearing of his initial position from his final position = 180° - (θ + 60°)

θ = 15°

Bearing of his initial position from his final position = 180° - (15° + 60°)

Bearing of his initial position from his final position = 180° - 75°

Bearing of his initial position from his final position = 105°