Volume = 264 cm³

Radius (r) = 6 cm

π = $\frac{22}{7}$

264 = $\frac{22}{7}$ x 6² x $\frac{\mathrm{h}}{3}$

264 = $\frac{\mathrm{22\; x\; 36\; x\; h}}{\mathrm{7\; x\; 3}}$

Get rid of the fraction by multiplying both sides by the denominator 7 x 3.

264 x 7 x 3 = 22 x 36 x h

Divide both sides by 22 x 36

h = $\frac{\mathrm{264\; x\; 7\; x\; 3}}{\mathrm{22\; x\; 36}}$ = 7 cm

From Pythagorean theorem,

The hypothenuse (c) is the longest side. The side facing the right-angle (∟)

c² = 6² + 8²

c² = 100

Take square root of both sides.

c = $\sqrt{\mathrm{100}}$ = 10 cm

Perimeter is the sum of all the sides of a shape.

The perimeter of the rhombus = c + c + c + c

The perimeter of the rhombus = 4c

The perimeter of the rhombus = 4 x 10 cm

The perimeter of the rhombus = 40 cm

Radius (r) = 3 cm

π = $\frac{22}{7}$

Height (h) = 4 cm

Total surface area = 2 x $\frac{22}{7}$ x 3² + 2 x $\frac{22}{7}$ x 3 x 4 cm²

Total surface area = 132 cm²

Distance covered in one complete revolution = the circumference of the wheel

Distance covered in the 8 complete revolutions = 8 x the circumference of the wheel

Circumference = 2 x π x radius

Distance covered in the 8 complete revolutions = 8 x 2 x π x radius

Radius = $\frac{\mathrm{Diameter}}{2}$ = $\frac{\mathrm{21\; cm}}{2}$ = 10.5 cm

π = $\frac{22}{7}$

Distance covered in the 8 complete revolutions = 8 x 2 x $\frac{22}{7}$ x 10.5 cm

Distance covered in the 8 complete revolutions = 528 cm

Perimeter is the sum of all the sides of a shape.

A square has the same lengths (L) for all 4 sides.

Perimeter of a square = L + L + L + L = 4L

Area of a square = Length (L) x Length (L) = L²

Area of the square parcel of land = 256 m²

L² = 256

Take square root of both sides.

L = $\sqrt{\mathrm{256}}$ = 16 m

Perimeter of the square parcel of land = 4L

Perimeter of the square parcel of land = 4 x 16 m = 64 m

The rectangular field has the same perimeter.

Perimeter of the rectangular field = 64 m

Rectangle has two of the lengths equal and two of the breadth equal.

Perimeter of a rectangle = Length(L) + Length(L) + Breadth(B) + Breadth (B)

Perimeter of a rectangle = L + L + B + B

Perimeter of a rectangle = 2L + 2B

Perimeter of the rectangular field = 64 m

The length of the rectangular field = 20 m

2 x 20 m + 2B = 64 m

40 m + 2B = 64 m

2B = 64 m - 40 m

2B = 24 m

Divide both sides by 2.

B = $\frac{\mathrm{24\; m}}{2}$ = 12 m

The breadth of the rectangular field = 12 m

Area of a rectangle = Length x Breadth

Area of the rectangular field = 20 m x 12 m = 240 m²

Total surface area = 2(12 x 7 + 7 x 5 + 12 x 5) cm²

Total surface area = 358 cm²