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1.
Find the 5th term of the sequence 2, 5, 10, 17....?
22
24
36
26
The rule of the sequence is n2 + 1
Where n is the number of term.
When n = 1 → 12 + 1 = 1 + 1 = 2
When n = 2 → 22 + 1 = 4 + 1 = 5
When n = 3 → 32 + 1 = 9 + 1 = 10
When n = 4 → 42 + 1 = 16 + 1 = 17
When n = 5 → 52 + 1 = 25 + 1 = 26
2.
The last term of the sequence: 7, 11, 15, ... is 115. Find the number of terms in the sequence.
28
29
27
Un = U1 + (n-1)d
Where n is the number of terms
Un is the nth term
U1 is the first term
d is the common difference
d is obtained by subtracting preceding term from succeeding term
Note: a sequence is linear when the intervals (common difference) between the numbers are the same.
Common difference (d) = 11 - 7 = 15 - 11 = 4
Un = 115
U1 = 7
115 = 7 + (n - 1) x 4
115 = 7 + 4n - 4
115 = 7 - 4 + 4n
115 = 3 + 4n
115 - 3 = 4n
112 = 4n
Divide both sides by 4
n = 112 4
n = 28
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