A stock broker, Kojo, invested some amount in two accounts which pay 11% and 10% simple interest annually. The amount invested at 11% is 140% of the amount invested at 10%. After 3 years, he earned a total of GH₵ 22,580.60 as interest. How much was invested at 11%?
Show Solution
Simple Interest
Simple Interest =
Let y = amount invested at 10%
The amount invested at 11% is 140% of the amount invested at 10%
Amount invested at 11% = x y = 1.4y
3 years = 3.5 years
Time (T) = 3.5
Interest at 11%
Principal = 1.4y
Rate = 11%
Interest at 11% =
Interest at 11% =
Interest at 11% = 0.539y
Interest at 10%
Principal = y
Rate = 10%
Interest at 10% =
Interest at 10% =
Interest at 10% = 0.35y
Total interest = Interest at 11% + Interest at 10%
Total interest = GH₵ 22,580.60
22580.60 = 0.539y + 0.35y
22580.60 = 0.889y
Divide both sides by 0.889
y =
y = 25400
Amount invested at 10% = GH₵ 25,400
Amount invested at 11% = 1.4y = 1.4 x y
Amount invested at 11% = 1.4 x 25400 = GH₵ 35,560
Note: 1 mark is deducted for answers without unit.