The mean age, in years, of t girls in a class was 17.6. At the end of the academic year, 4 girls aged 16, 19, 20 and 17 were dismissed. The new mean age of girls in the class became 0.2 less than the original mean.
Find the value of t.
Show Solution
Mean
Mean =
Sum of items = Mean x Number of items.
Mean = 17.6
Number of girls in the class = t
Sum of the ages of girls = 17.6 x t = 17.6t
When the girls where dismissed, the sum of the ages reduced to 17.6t - (16 + 19 + 20 + 17) and the number of girls reduced to t - 4
Note: 4 girls were dismissed.
New sum of ages = 17.6t - (16 + 19 + 20 + 17)
New sum of ages = 17.6t - 72
New number of girls = t - 4
New mean =
The new mean age of girls in the class became 0.2 less than the original mean.
Original mean = 17.6
New mean = 17.6 - 0.2 = 17.4
= 17.4
Get rid of the fraction by multiplying both sides by the denominator t - 4
x (t - 4) = 17.4 x (t - 4)
17.6t - 72 = 17.4t - 69.6
17.6t - 17.4t = 72 - 69.6
0.2t = 2.4
Divide both sides by 0.2
t = = 12